turbo sizing
#1
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turbo sizing
What do you guys think of this turbo,what sort of power do you think it would make on a 13b bridge.
Compressor,turbine maps attached.
http://img298.imageshack.us/my.php?i...an000111ha.png
http://img298.imageshack.us/my.php?i...an000123tg.png
Compressor,turbine maps attached.
http://img298.imageshack.us/my.php?i...an000111ha.png
http://img298.imageshack.us/my.php?i...an000123tg.png
Last edited by 13b rew; 07-06-05 at 04:40 PM.
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Thanks Howard,how did you arrive at those figures,am novice when it comes to turbo sizing,am trying to learn also!!!!!!!!!!!!
Gd question sdminus! Is that fly or wheels.
Looking to make 550rwhp,was told this turbo would produce that?
Gd question sdminus! Is that fly or wheels.
Looking to make 550rwhp,was told this turbo would produce that?
#5
Racing Rotary Since 1983
iTrader: (6)
sorry.... those are rwhp #s.
as far as how i derive them...
i use two methods that both end up at the same approx spot.
lbs/minute times 10 divided by 1.3 results in rear wheel rotary hp
lbs/minute times 14.471 equals CFM divided by 1.92.
these formulas have worked well for me over the years. the hp # assumes everything is optimised.
howard coleman
as far as how i derive them...
i use two methods that both end up at the same approx spot.
lbs/minute times 10 divided by 1.3 results in rear wheel rotary hp
lbs/minute times 14.471 equals CFM divided by 1.92.
these formulas have worked well for me over the years. the hp # assumes everything is optimised.
howard coleman
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#11
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Originally Posted by howard coleman
max flow off the compressor map is approx 73.
max flow at 1 bar is 68.
5 lbs/min times 10/1.3 is 38 rw rotary hp.
howard coleman
max flow at 1 bar is 68.
5 lbs/min times 10/1.3 is 38 rw rotary hp.
howard coleman
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At 1 bar turbo flows 68lbs/min which = 497 rwhp.
Maximum flow of turbo according to compressor map is 73lbs/min.
73-68 = 5lbs/min which = extra 38 rwhp at maximum flow
497 + 38 = 535 rwhp
Gary
Maximum flow of turbo according to compressor map is 73lbs/min.
73-68 = 5lbs/min which = extra 38 rwhp at maximum flow
497 + 38 = 535 rwhp
Gary
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Originally Posted by 13b rew
At 1 bar turbo flows 68lbs/min which = 497 rwhp.
Maximum flow of turbo according to compressor map is 73lbs/min.
73-68 = 5lbs/min which = extra 38 rwhp at maximum flow
497 + 38 = 535 rwhp
Gary
Maximum flow of turbo according to compressor map is 73lbs/min.
73-68 = 5lbs/min which = extra 38 rwhp at maximum flow
497 + 38 = 535 rwhp
Gary
Where did you get the equation (xlbs/min*10)/1.3=rotary hp?
because if I go by that equation 68lbs/min is not 497 its 523.
#15
Racing Rotary Since 1983
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since i started all the confusion i should straighten it out. i do apologise.
here's how i see it.
2 methods.
given:
68 lbs per minute at one bar or 2.0 pressure ratio.
68 times 10 divided by 1.3 equals 523 rw rotary hp
68 times 14.471 to get cfm (984) divided by 1.92 equals 512 rw rotary hp
at max flow 73 pounds per minute
73X10/1.3 equals 561
73X 14.471 equals 1056 CFM divided by 1.92 equals 550
howard coleman
here's how i see it.
2 methods.
given:
68 lbs per minute at one bar or 2.0 pressure ratio.
68 times 10 divided by 1.3 equals 523 rw rotary hp
68 times 14.471 to get cfm (984) divided by 1.92 equals 512 rw rotary hp
at max flow 73 pounds per minute
73X10/1.3 equals 561
73X 14.471 equals 1056 CFM divided by 1.92 equals 550
howard coleman
#16
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iTrader: (8)
Originally Posted by howard coleman
since i started all the confusion i should straighten it out. i do apologise.
here's how i see it.
2 methods.
given:
68 lbs per minute at one bar or 2.0 pressure ratio.
68 times 10 divided by 1.3 equals 523 rw rotary hp
68 times 14.471 to get cfm (984) divided by 1.92 equals 512 rw rotary hp
at max flow 73 pounds per minute
73X10/1.3 equals 561
73X 14.471 equals 1056 CFM divided by 1.92 equals 550
howard coleman
here's how i see it.
2 methods.
given:
68 lbs per minute at one bar or 2.0 pressure ratio.
68 times 10 divided by 1.3 equals 523 rw rotary hp
68 times 14.471 to get cfm (984) divided by 1.92 equals 512 rw rotary hp
at max flow 73 pounds per minute
73X10/1.3 equals 561
73X 14.471 equals 1056 CFM divided by 1.92 equals 550
howard coleman
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Originally Posted by howard coleman
since i started all the confusion i should straighten it out. i do apologise.
here's how i see it.
2 methods.
given:
68 lbs per minute at one bar or 2.0 pressure ratio.
68 times 10 divided by 1.3 equals 523 rw rotary hp
howard coleman
here's how i see it.
2 methods.
given:
68 lbs per minute at one bar or 2.0 pressure ratio.
68 times 10 divided by 1.3 equals 523 rw rotary hp
howard coleman
assuming optimized everything including tuning...
497 at 14.5 psi.
(68lb/minx10)/1.3=523 not 497
edit* Ok I think I know what you are trying to say. You are saying that it flows 68lbs/min at 1 bar and max flow is reached at 22 psi ?
Last edited by MARTIN; 07-09-05 at 11:23 PM.
#18
Savanna Rx-7
Originally Posted by t-von
Ok what if this turbo was on a 20b?
T-von,
I think that regardless if its (turbine) max hp is XXX its max would still be XXX regardless of the motor it was put on, becasue it can only flow X lbs/min of air.
I could be wrong though as I am certainly not a turbo guru.
kenn
#19
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Originally Posted by kenn_chan
T-von,
I think that regardless if its (turbine) max hp is XXX its max would still be XXX regardless of the motor it was put on, becasue it can only flow X lbs/min of air.
I could be wrong though as I am certainly not a turbo guru.
kenn
I think that regardless if its (turbine) max hp is XXX its max would still be XXX regardless of the motor it was put on, becasue it can only flow X lbs/min of air.
I could be wrong though as I am certainly not a turbo guru.
kenn
#20
Senior Member
yes i think you rite about that. aswell as chosing a larger turbine wheel, the compressor would aproach max flow at lower boost level or lower rpm on a 20b. so this is were you can use the same compressor but with a different trim that has better efficiency at lower boost levels to develop the same power more effectively.
I think the trim can play a big role on boost efficiency.
I think the trim can play a big role on boost efficiency.
Originally Posted by t-von
I understand that but the reason I brought up the 20b is because it has 50% more displacment than the 13b. Therefore wouldn't this same turbo make the same amounts of hp but at a lower boost level? I just wanted to see how much boost it would take for a 20B to make the same 561 (max flow) hp.
Last edited by bobybeach; 07-11-05 at 03:10 AM.
#21
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Originally Posted by bobybeach
yes i think you rite about that. aswell as chosing a larger turbine wheel, the compressor would aproach max flow at lower boost level or lower rpm on a 20b. so this is were you can use the same compressor but with a different trim that has better efficiency at lower boost levels to develop the same power more effectively.
I think the trim can play a big role on boost efficiency.
I think the trim can play a big role on boost efficiency.
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