torque?
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torque?
so if my fc has 138 torque at 3800 rpm how much torque do i have up hi like 6300 6500 rpm. do you lose alot and its all hp after 3800 or do you only lose a lil? please help
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#10
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Torque normally falls off as the engine approaches redline.
This is just the normal dynamics and physics of the internal combustion engine.
There are tricks to keep the torque up - i.e. VDI, switching short / long runners, etc., but torque tends to fall on the top end.
Sorry, but if you want "gobs of torque", you need to go forced induction or more displacement.
-Ted
This is just the normal dynamics and physics of the internal combustion engine.
There are tricks to keep the torque up - i.e. VDI, switching short / long runners, etc., but torque tends to fall on the top end.
Sorry, but if you want "gobs of torque", you need to go forced induction or more displacement.
-Ted
#11
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a stock engine making 146 HP at 6500 rpm is making 118 lb-ft of torque at that same 6500 rpm. HP is a function of torque. HP, Torque, and RPM. take any two and you can find out the third
#12
Originally Posted by RETed
Torque normally falls off as the engine approaches redline.
This is just the normal dynamics and physics of the internal combustion engine.
There are tricks to keep the torque up - i.e. VDI, switching short / long runners, etc., but torque tends to fall on the top end.
Sorry, but if you want "gobs of torque", you need to go forced induction or more displacement.
-Ted
This is just the normal dynamics and physics of the internal combustion engine.
There are tricks to keep the torque up - i.e. VDI, switching short / long runners, etc., but torque tends to fall on the top end.
Sorry, but if you want "gobs of torque", you need to go forced induction or more displacement.
-Ted
LOL
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Originally Posted by Green_Streak
a stock engine making 146 HP at 6500 rpm is making 118 lb-ft of torque at that same 6500 rpm. HP is a function of torque. HP, Torque, and RPM. take any two and you can find out the third
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^
which is why the torque and hp curves on all dyno graphs should cross at 5252 rpm, because (5252/5252) equals one, and so horsepower will always equal torque at that specific rpm.
which is why the torque and hp curves on all dyno graphs should cross at 5252 rpm, because (5252/5252) equals one, and so horsepower will always equal torque at that specific rpm.
#18
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Originally Posted by 7romanstatesmen
^
which is why the torque and hp curves on all dyno graphs should cross at 5252 rpm, because (5252/5252) equals one, and so horsepower will always equal torque at that specific rpm.
which is why the torque and hp curves on all dyno graphs should cross at 5252 rpm, because (5252/5252) equals one, and so horsepower will always equal torque at that specific rpm.
Some DynoJet graphs like to scale different torque and hp axes, so be careful about this.
-Ted
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As long as we're on the subject here, just a little fyi for anyone that doesn't know; Peak Torque ALWAYS occurs at Peak Volumetric Efficiency. Given that, it's easy to understand why Turbo/Supercharging help out Torque alot.
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Originally Posted by RETed
That is correct IF the torque and hp scales are exactly the same.
Some DynoJet graphs like to scale different torque and hp axes, so be careful about this.
-Ted
Some DynoJet graphs like to scale different torque and hp axes, so be careful about this.
-Ted
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sorry but i don't get it, well it's not that i don't get it just the math isn't working out. Lets go with the new passat it has 276hp at 6200 and 266lb-ft at 2750 so if R=(H/T)*5252 then R=(276/266)*5252 that equals 5449.44 which is niether the rpm of the HP or Torque, Assuming it did work out right would R be the rpm of the HP or torque? even with H=T*(R/5252) Then H=266*(6200/5252) that would mean 314hp unless you ment r is the rpm or the torque in which case H=266*(2750/5252) and that would mean 139.28hp
not trying to be a dick just trying to figure out why it won't work for me
not trying to be a dick just trying to figure out why it won't work for me
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