20b manifold are done
In a high load application the center divider will cop a beating, and eventually crack and pieces will fly through the turbo, destroying the turbine wheel. Seen it on my mates T04Z car. Grind out the divide and sell the manifold to only suit single entry T4 turbine housings. They are available in 0.96 P-trim, 1.14 P-trim and 0.96 Q-trim anyhow.
Divided exhaust housings only work on engines with pipe counts a multiple of 2. They are brilliant on twin rotors, 4 cylinders 6 cylinders etc. It is going to be a flow restriction and a point of failure on a 20b or an inline 5 engine.
Divided exhaust housings only work on engines with pipe counts a multiple of 2. They are brilliant on twin rotors, 4 cylinders 6 cylinders etc. It is going to be a flow restriction and a point of failure on a 20b or an inline 5 engine.
The reason I ask is to take advantage of some sort of scavaging effect. I have seen them(3rotors) make 50 rwhp more and spool quicker because of this. It is a little more difficult to do but if done properly I think it will be safe.
The trick may be at what point that third runner gets divided. A 1 2 3 pulse in the header above would be divided 1 and half of 2 into the front and the other half of 2 and all of 3 into the back. Again I belive the trick will be number 2 and how is gets distributed, and therefore my question is asked how this one does it.
The trick may be at what point that third runner gets divided. A 1 2 3 pulse in the header above would be divided 1 and half of 2 into the front and the other half of 2 and all of 3 into the back. Again I belive the trick will be number 2 and how is gets distributed, and therefore my question is asked how this one does it.
The reason I ask is to take advantage of some sort of scavaging effect. I have seen them(3rotors) make 50 rwhp more and spool quicker because of this. It is a little more difficult to do but if done properly I think it will be safe.
The trick may be at what point that third runner gets divided. A 1 2 3 pulse in the header above would be divided 1 and half of 2 into the front and the other half of 2 and all of 3 into the back. Again I belive the trick will be number 2 and how is gets distributed, and therefore my question is asked how this one does it.
The trick may be at what point that third runner gets divided. A 1 2 3 pulse in the header above would be divided 1 and half of 2 into the front and the other half of 2 and all of 3 into the back. Again I belive the trick will be number 2 and how is gets distributed, and therefore my question is asked how this one does it.
You cannot flow 3 M&Ms exactly divided into 2 mouths.
2 M&Ms 2 Mouths
3 M&Ms 3 Mouths (there are not many 3 volute turbos kicking around)
3 M&Ms 1 Mouth
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you can too flow 3 m&m's perfectly into two mouths
1/2 of 1 goes to one and two; 1/2 of 2 goes to 1 and 2; 1/2 of 3 goes to 1 and 2
i have no idea who would try to divide a manifold like this but it seems like it would be the proper way to divide a 3 rotor.
1/2 of 1 goes to one and two; 1/2 of 2 goes to 1 and 2; 1/2 of 3 goes to 1 and 2
i have no idea who would try to divide a manifold like this but it seems like it would be the proper way to divide a 3 rotor.
