NEW Rotary Parts.....
#104
Senior Member
Join Date: Nov 2008
Location: Czech republic
Posts: 357
Likes: 0
Received 0 Likes
on
0 Posts
1x86mm.........58,05cm² but less friction
1x90mm.........63,585cm²
+one large throttle plate takes less space than 3 small...
#106
Rotary Freak
iTrader: (28)
Join Date: Jun 2009
Location: Ontario, Canada
Posts: 2,089
Likes: 0
Received 0 Likes
on
0 Posts
Ok this took me a while to figure out how you got those values....
First you are putting the comma in a different spot then I am use to seeing and that hurt my little brain lol
Now if I have done this correcly the Feed unit flows. 6,615 cm
This is assuming all three butterflys are bored out 4mm.
First you are putting the comma in a different spot then I am use to seeing and that hurt my little brain lol
Now if I have done this correcly the Feed unit flows. 6,615 cm
This is assuming all three butterflys are bored out 4mm.
#107
ERTW
iTrader: (4)
Total area of 3 x 50mm bores = 3*pi*50^2/4 = 5890.486 mm^2
The equivalent area of one bore would have to be the same, so in order to determine the equivalent diameter of one opening you would multiply by 4, divide by PI and take the square root.
(5890.486 * 4/PI)^0.5 = 86.6mm
In terms of "friction", in flow dynamics you would look at the "wetted perimeter" difference, in this case determined by the difference in circumference of 3 circles versus one larger circle:
Circumference is PI*d, so for 3x50mm bores, it would be 471.24 mm.
For one 86.6mm bore, it would be 272.06 mm
...and for a 90mm bore, it would be 282.74 mm or exactly 60% of the original FD throttle body.
A lower circumference ultimately results in reduced drag since the air interferes with a lower surface area, which is where most of the benefit comes from.
#110
DPG Burnout
iTrader: (53)
Area = PI*r^2 or PI*d^2/4
Total area of 3 x 50mm bores = 3*pi*50^2/4 = 5890.486 mm^2
The equivalent area of one bore would have to be the same, so in order to determine the equivalent diameter of one opening you would multiply by 4, divide by PI and take the square root.
(5890.486 * 4/PI)^0.5 = 86.6mm
In terms of "friction", in flow dynamics you would look at the "wetted perimeter" difference, in this case determined by the difference in circumference of 3 circles versus one larger circle:
Circumference is PI*d, so for 3x50mm bores, it would be 471.24 mm.
For one 86.6mm bore, it would be 272.06 mm
...and for a 90mm bore, it would be 282.74 mm or exactly 60% of the original FD throttle body.
A lower circumference ultimately results in reduced drag since the air interferes with a lower surface area, which is where most of the benefit comes from.
Total area of 3 x 50mm bores = 3*pi*50^2/4 = 5890.486 mm^2
The equivalent area of one bore would have to be the same, so in order to determine the equivalent diameter of one opening you would multiply by 4, divide by PI and take the square root.
(5890.486 * 4/PI)^0.5 = 86.6mm
In terms of "friction", in flow dynamics you would look at the "wetted perimeter" difference, in this case determined by the difference in circumference of 3 circles versus one larger circle:
Circumference is PI*d, so for 3x50mm bores, it would be 471.24 mm.
For one 86.6mm bore, it would be 272.06 mm
...and for a 90mm bore, it would be 282.74 mm or exactly 60% of the original FD throttle body.
A lower circumference ultimately results in reduced drag since the air interferes with a lower surface area, which is where most of the benefit comes from.
#113
Goodfalla Engine Complete
iTrader: (28)
However, I doubt that it only helps the high end. Your main velocity point is the port and the point where air is divided amongst the intake manifold runners. Smoothing out the flow before the runners (directly) should help throughout the entire powerband.
#122
Pricing on the exhaust sleeves???
In regards to the FD TB, what needs to be kept from the stock TB for functionality?
Thanks again to everyone...we are trying to build the best parts for the Rotary community.
Last edited by Rotary-Works.com; 01-14-10 at 12:15 AM.