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Here is a quote to put a damper on water injection

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Old Jun 27, 2005 | 05:13 PM
  #101  
dubulup's Avatar
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water is on the right side...if we add it to the left (WI), it moves the equation further from the product.
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Old Jun 27, 2005 | 05:24 PM
  #102  
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Originally Posted by dubulup
water is on the right side...if we add it to the left (WI), it moves the equation further from the product.
Huh? Le Chatelier's Principle simply states that if dynamic equilibrium is disturbed, the position of the equilibrium will move to offset that change. So if you add water to the left (reactants), the system will actually move to consume that water and shift the equation to the right (products).

The way to shift the equilibrium away from the products (ie to the reactants) would be to add water on the right, ie the products. That way, the system would flow backward, to produce the reactants.

I don't see how any of this is relevant, since water is NOT one of the reactants. I don't know what energy-related or rate-related change adding water to the reactant side would have, but I don't see it as helpful, and am pretty sure water itself is NOT partaking in the combustion process.
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Old Jun 27, 2005 | 06:20 PM
  #103  
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From: Pasadena, CA
Originally Posted by FDNewbie
Huh? Le Chatelier's Principle simply states that if dynamic equilibrium is disturbed, the position of the equilibrium will move to offset that change. So if you add water to the left (reactants), the system will actually move to consume that water and shift the equation to the right (products).

The way to shift the equilibrium away from the products (ie to the reactants) would be to add water on the right, ie the products. That way, the system would flow backward, to produce the reactants.

I don't see how any of this is relevant, since water is NOT one of the reactants. I don't know what energy-related or rate-related change adding water to the reactant side would have, but I don't see it as helpful, and am pretty sure water itself is NOT partaking in the combustion process.
Wow, Ramy...I'm impressed.

Yep, water is not a reactant in the combustion process. Its change is completely independent from the hydrocarbon/oxygen reaction.
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Old Jun 27, 2005 | 08:07 PM
  #104  
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Originally Posted by Kento
Wow, Ramy...I'm impressed.
LOL. I'm not retarded Kento That's like the simplest principle in chem haha. But yea...thanks. Chemistry (and biology) are my thing. That's my turf. They kinda have to be...unless I'm gonna carry a steady supply of bodybags To be frank, when it comes to physics and the in-depth automotive mechanics, I simply don't have the background, so it's like joe schmoe tryin to roll w/ the big dogs haha. I'm workin on it tho.
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Old Jun 27, 2005 | 08:22 PM
  #105  
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sabb or volvo ... found that they could replace a significant amout of the fuel being injected into the engine with water after the torque peak and not loose any tq. the idea being that after the tq peak a major role of the fuel is to keep the temps down a bit allowing for a controlled ignition.
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