Help Me Beat This Guy!!!
Originally posted by 911GT2
105m/h*1hr/60min*1min/60sec*5280ft/mile= 154 ft/sec.
But the other car is moving too. Lets say the other car is doing 100mph
100m/hr*1hr/60min*1min/60sec*5280ft/mile=146ft/min
These numbers are average speeds, and theory based, but 154-146= 8 ft. Which would be a bit less than 1 car length.
105m/h*1hr/60min*1min/60sec*5280ft/mile= 154 ft/sec.
But the other car is moving too. Lets say the other car is doing 100mph
100m/hr*1hr/60min*1min/60sec*5280ft/mile=146ft/min
These numbers are average speeds, and theory based, but 154-146= 8 ft. Which would be a bit less than 1 car length.
Lets say a car passes the 1/4 mark and you pass it one sec later at 100mph. You would have been
100mph % 60min= 1.666
for every minute it travels 1.666 miles
1.666 % 60sec= .0277
for every sec it travels .0277 miles
.0277 * 5280ft= 146ft
for every sec, a 100mph car will travel 146ft
This is just an average since there is no way of knowing the acceleration speeds
There is no way in hell a 13 sec car will only be ahead of a 14 sec car by only a car legnth, that's just stupid
Originally posted by AMRAAM4
Uhm yeah...not gonna argue because I see you as an arguing type just by your condescending, know-it-all tone coming out of nowhere.....but, your still wrong there sweet pee. Reason I know, my other car I ran a 14.93 in, I was going against a 57 Chevy who ran a 13.9...lets just say there wasn't half a ******* football field between us when we crossed the finish line.
Uhm yeah...not gonna argue because I see you as an arguing type just by your condescending, know-it-all tone coming out of nowhere.....but, your still wrong there sweet pee. Reason I know, my other car I ran a 14.93 in, I was going against a 57 Chevy who ran a 13.9...lets just say there wasn't half a ******* football field between us when we crossed the finish line.
Let us know your mph then we'll talk
Originally posted by AMRAAM4
Uhm yeah...not gonna argue because I see you as an arguing type just by your condescending, know-it-all tone coming out of nowhere.....but, your still wrong there sweet pee. Reason I know, my other car I ran a 14.93 in, I was going against a 57 Chevy who ran a 13.9...lets just say there wasn't half a ******* football field between us when we crossed the finish line.
Uhm yeah...not gonna argue because I see you as an arguing type just by your condescending, know-it-all tone coming out of nowhere.....but, your still wrong there sweet pee. Reason I know, my other car I ran a 14.93 in, I was going against a 57 Chevy who ran a 13.9...lets just say there wasn't half a ******* football field between us when we crossed the finish line.
Let us know your mph then we'll talk
Originally posted by LT1-7
You weren't racing heads up were you? When bracket racing you can sit at the line for 30sec and still run a 10 sec run
Let us know your mph then we'll talk
You weren't racing heads up were you? When bracket racing you can sit at the line for 30sec and still run a 10 sec run
Let us know your mph then we'll talk
this topic is getting ghey, lets drop it, mmK?
Time for a lesson, I will be as straight forward as possable
Formulae of Motion :
u = initial velocity
v = final velocity
a = acceleration
s = distance
t = time
Now please note that the usual unit of distance in physics is actually measured in meter's per second.
Lets assume for arguments sake that the two vehicles are moving along side each other travelling at a rate of
38 m/s <--meters per second translation 85 mph. This is going to be a quarter mile race so lets say for example
that at this 85 mph we have just arrived at the 1/8 mile mark (ie.) half way done the race. We now need a unit of
time measure so I'll say our RX-7's time at the 1/8 mile mark will be 8.8 seconds for our example. Let us assume
for a moment that the gentleman in his heavily modified Mopar Camry wagon geared his transmission too low and
now met his top speed of 85 mph at the 1/8 mile point we can come up with a formula to calculate differentiation
of distance and time between the vehicles at completion of the race.
(Lot's of assumptions I know but hey thats physics!)
Now using this our almighty formulae:
s=ut+1/2 at^2
Now we are going to leave this camry in the dust cause we have NAwwZZZ!!!!
We hit the Nawzz button and wham!!! 1.5 seconds later we are now moving at 120mph, but alas our car blows all 6 apex seals...
Crap on a crutch!!!shoulda sprung for the 3 mill Hurleys!!! However with a air drag co-efficient unparalleled in the
areo/space industry being(pefect
) we can now see the difference between the vehicle moving at said rates
for speed 85mph or 38 m/s and us at 120mph or 53.6 m/s
accelleration= velocity change/ time taken
a=53.6m/s^-1 - 38m/s-1 /1.5 = 10.4ms^-2
distance s=ut+1/2 at²
s=(38x1.5)+1/2(10.4x1.5²)=57+1/2 (10.4x2.25)=57+11.7=68.7m or 225 feet
ok surmising that we have 1320 feet in 1/4 of a mile and we have travelled 660+225=885 that leaves us 435 feet or 132.5 meters
to go sooo....132.5/53.6 =2.47 seconds until we cross finish line, total time for us is 8.8+1.5+2.47= 12.77 seconds in the 1320. YIPEE
Now how many feet did we kick that Camry's *** by? lets see. travelling at said rate of speed 38m/sCamry is at 38 x (1.5+2.47)=495 ft
travelled in same amount of time that we completed the 1320 so....1320-660+495= 165 feet at the end of race and a final time of 14.09 seconds.
Hope this helps!!!
Formulae of Motion :
u = initial velocity
v = final velocity
a = acceleration
s = distance
t = time
Now please note that the usual unit of distance in physics is actually measured in meter's per second.
Lets assume for arguments sake that the two vehicles are moving along side each other travelling at a rate of
38 m/s <--meters per second translation 85 mph. This is going to be a quarter mile race so lets say for example
that at this 85 mph we have just arrived at the 1/8 mile mark (ie.) half way done the race. We now need a unit of
time measure so I'll say our RX-7's time at the 1/8 mile mark will be 8.8 seconds for our example. Let us assume
for a moment that the gentleman in his heavily modified Mopar Camry wagon geared his transmission too low and
now met his top speed of 85 mph at the 1/8 mile point we can come up with a formula to calculate differentiation
of distance and time between the vehicles at completion of the race.
(Lot's of assumptions I know but hey thats physics!)
Now using this our almighty formulae:
s=ut+1/2 at^2
Now we are going to leave this camry in the dust cause we have NAwwZZZ!!!!
We hit the Nawzz button and wham!!! 1.5 seconds later we are now moving at 120mph, but alas our car blows all 6 apex seals...
Crap on a crutch!!!shoulda sprung for the 3 mill Hurleys!!! However with a air drag co-efficient unparalleled in the
areo/space industry being(pefect
) we can now see the difference between the vehicle moving at said ratesfor speed 85mph or 38 m/s and us at 120mph or 53.6 m/s
accelleration= velocity change/ time taken
a=53.6m/s^-1 - 38m/s-1 /1.5 = 10.4ms^-2
distance s=ut+1/2 at²
s=(38x1.5)+1/2(10.4x1.5²)=57+1/2 (10.4x2.25)=57+11.7=68.7m or 225 feet
ok surmising that we have 1320 feet in 1/4 of a mile and we have travelled 660+225=885 that leaves us 435 feet or 132.5 meters
to go sooo....132.5/53.6 =2.47 seconds until we cross finish line, total time for us is 8.8+1.5+2.47= 12.77 seconds in the 1320. YIPEE
Now how many feet did we kick that Camry's *** by? lets see. travelling at said rate of speed 38m/sCamry is at 38 x (1.5+2.47)=495 ft
travelled in same amount of time that we completed the 1320 so....1320-660+495= 165 feet at the end of race and a final time of 14.09 seconds.
Hope this helps!!!
Originally posted by AMRAAM4
no it was not bracket racing.
this topic is getting ghey, lets drop it, mmK?
no it was not bracket racing.
this topic is getting ghey, lets drop it, mmK?
If it wans't bracket racing you were doing than what the hell was it? Even heads up drag racing starts when you leave the line, I believe
Anyways, I'll drop it if you drop it
Originally posted by AMRAAM4
Uhm yeah...not gonna argue because I see you as an arguing type just by your condescending, know-it-all tone coming out of nowhere.....but, your still wrong there sweet pee. Reason I know, my other car I ran a 14.93 in, I was going against a 57 Chevy who ran a 13.9...lets just say there wasn't half a ******* football field between us when we crossed the finish line.
Uhm yeah...not gonna argue because I see you as an arguing type just by your condescending, know-it-all tone coming out of nowhere.....but, your still wrong there sweet pee. Reason I know, my other car I ran a 14.93 in, I was going against a 57 Chevy who ran a 13.9...lets just say there wasn't half a ******* football field between us when we crossed the finish line.
The distance isnt constant for a second time difference. It is realitive to the speed. So you trapped at probably 90ish mph so you were probably 100-120 feet back I dont feel like doing the math.
But arguing on the internet is like the special olympics. If if you win you are still retarded.
thanx thouse who helped. it made a huge difference and now i am a good second faster! it is all in off the line launching.. thanx pax, i was ghonna come to the auto/x but found out is is on sunday, cant make it now,, good luck and have fun!
chris
chris
As a rule of thumb: at 100mph in the 1/4 mile a tenth of a second is one car length. So if you lose by one tenth aof a second saying you only do 100mph in the 1/4 your front bumper is even with their back bumper, one car length. If a car is 10' then one second behind would result in being beat by 100'.
If your not afraid of burning your cluch then i have your perfect lonch. First you have to find the spot on your throtle that lets you sit at 4k. Then as the lights are about to turn or what ever your starter is then you start to slide the cluch. You need to time it so you get to the spot where it wants to start kreeping up the light is about to turn. When the light turns slide the cluch out don't drop it but to stuff the gas to the floor. This eliminates the tire hop but you will get a little burn out. Don't get too exsited about the lonch bercause you need to shift out almost immeaditly. This is very hard on your cluch but i seen you already have a stage three in. This has aloud me to take STi's and Evos off the line.
O and for the shifting into your next gears, you need to practis letting your gas out just a little bit so your rpms stay up there and then dump the cluch. B carfull because second will kick out your *** end doing this. A lighter fly wheel or the Apex'i AVC-R boost control will help eliminate that turbo lag and b a little easer on your car.
God Chris, you really started something!
I had to weed through all this BS just to see what is going on.
Your car feels very fast - especially up top.
I think between the street port and moded twins, you have just a little more lag than a stock FD, until that second turbo kicks in. That is probably why he is getting you at the start.
A FWD car should not have the advantage at the start, unless he has a drag setup and is really good at launching his car. I think you just need to practice and maybe, as mentioned, get some nice, wide tires.
The 'back and forth' is from your shifting skill and shift point. As pax said, your dyno shows you need to shift sooner. And possibly, since your car is not tuned, you may be out of the powerband between shifts, causing a lag as you come back into it.
I had to weed through all this BS just to see what is going on.
Your car feels very fast - especially up top.
I think between the street port and moded twins, you have just a little more lag than a stock FD, until that second turbo kicks in. That is probably why he is getting you at the start.
A FWD car should not have the advantage at the start, unless he has a drag setup and is really good at launching his car. I think you just need to practice and maybe, as mentioned, get some nice, wide tires.
The 'back and forth' is from your shifting skill and shift point. As pax said, your dyno shows you need to shift sooner. And possibly, since your car is not tuned, you may be out of the powerband between shifts, causing a lag as you come back into it.
Originally posted by HUGH
Time for a lesson, I will be as straight forward as possable
Formulae of Motion :
u = initial velocity
v = final velocity
a = acceleration
s = distance
t = time
Now please note that the usual unit of distance in physics is actually measured in meter's per second.
Lets assume for arguments sake that the two vehicles are moving along side each other travelling at a rate of
38 m/s <--meters per second translation 85 mph. This is going to be a quarter mile race so lets say for example
that at this 85 mph we have just arrived at the 1/8 mile mark (ie.) half way done the race. We now need a unit of
time measure so I'll say our RX-7's time at the 1/8 mile mark will be 8.8 seconds for our example. Let us assume
for a moment that the gentleman in his heavily modified Mopar Camry wagon geared his transmission too low and
now met his top speed of 85 mph at the 1/8 mile point we can come up with a formula to calculate differentiation
of distance and time between the vehicles at completion of the race.
(Lot's of assumptions I know but hey thats physics!)
Now using this our almighty formulae:
s=ut+1/2 at^2
Now we are going to leave this camry in the dust cause we have NAwwZZZ!!!!
We hit the Nawzz button and wham!!! 1.5 seconds later we are now moving at 120mph, but alas our car blows all 6 apex seals...
Crap on a crutch!!!shoulda sprung for the 3 mill Hurleys!!! However with a air drag co-efficient unparalleled in the
areo/space industry being(pefect
) we can now see the difference between the vehicle moving at said rates
for speed 85mph or 38 m/s and us at 120mph or 53.6 m/s
accelleration= velocity change/ time taken
a=53.6m/s^-1 - 38m/s-1 /1.5 = 10.4ms^-2
distance s=ut+1/2 at²
s=(38x1.5)+1/2(10.4x1.5²)=57+1/2 (10.4x2.25)=57+11.7=68.7m or 225 feet
ok surmising that we have 1320 feet in 1/4 of a mile and we have travelled 660+225=885 that leaves us 435 feet or 132.5 meters
to go sooo....132.5/53.6 =2.47 seconds until we cross finish line, total time for us is 8.8+1.5+2.47= 12.77 seconds in the 1320. YIPEE
Now how many feet did we kick that Camry's *** by? lets see. travelling at said rate of speed 38m/sCamry is at 38 x (1.5+2.47)=495 ft
travelled in same amount of time that we completed the 1320 so....1320-660+495= 165 feet at the end of race and a final time of 14.09 seconds.
Hope this helps!!!
Time for a lesson, I will be as straight forward as possable
Formulae of Motion :
u = initial velocity
v = final velocity
a = acceleration
s = distance
t = time
Now please note that the usual unit of distance in physics is actually measured in meter's per second.
Lets assume for arguments sake that the two vehicles are moving along side each other travelling at a rate of
38 m/s <--meters per second translation 85 mph. This is going to be a quarter mile race so lets say for example
that at this 85 mph we have just arrived at the 1/8 mile mark (ie.) half way done the race. We now need a unit of
time measure so I'll say our RX-7's time at the 1/8 mile mark will be 8.8 seconds for our example. Let us assume
for a moment that the gentleman in his heavily modified Mopar Camry wagon geared his transmission too low and
now met his top speed of 85 mph at the 1/8 mile point we can come up with a formula to calculate differentiation
of distance and time between the vehicles at completion of the race.
(Lot's of assumptions I know but hey thats physics!)
Now using this our almighty formulae:
s=ut+1/2 at^2
Now we are going to leave this camry in the dust cause we have NAwwZZZ!!!!
We hit the Nawzz button and wham!!! 1.5 seconds later we are now moving at 120mph, but alas our car blows all 6 apex seals...
Crap on a crutch!!!shoulda sprung for the 3 mill Hurleys!!! However with a air drag co-efficient unparalleled in the
areo/space industry being(pefect
) we can now see the difference between the vehicle moving at said ratesfor speed 85mph or 38 m/s and us at 120mph or 53.6 m/s
accelleration= velocity change/ time taken
a=53.6m/s^-1 - 38m/s-1 /1.5 = 10.4ms^-2
distance s=ut+1/2 at²
s=(38x1.5)+1/2(10.4x1.5²)=57+1/2 (10.4x2.25)=57+11.7=68.7m or 225 feet
ok surmising that we have 1320 feet in 1/4 of a mile and we have travelled 660+225=885 that leaves us 435 feet or 132.5 meters
to go sooo....132.5/53.6 =2.47 seconds until we cross finish line, total time for us is 8.8+1.5+2.47= 12.77 seconds in the 1320. YIPEE
Now how many feet did we kick that Camry's *** by? lets see. travelling at said rate of speed 38m/sCamry is at 38 x (1.5+2.47)=495 ft
travelled in same amount of time that we completed the 1320 so....1320-660+495= 165 feet at the end of race and a final time of 14.09 seconds.
Hope this helps!!!
wow, this thread is great. ive learned lots of math, and i learned that tensecond1320 is a 12 year old tard that loves to tell stories.
*gets another bag of popcorn and waits for tensecond1320 to respond to him getting
over and over
*gets another bag of popcorn and waits for tensecond1320 to respond to him getting
over and over
Originally posted by SNracing
wow, this thread is great. ive learned lots of math, and i learned that tensecond1320 is a 12 year old tard that loves to tell stories.
*gets another bag of popcorn and waits for tensecond1320 to respond to him getting
over and over
wow, this thread is great. ive learned lots of math, and i learned that tensecond1320 is a 12 year old tard that loves to tell stories.
*gets another bag of popcorn and waits for tensecond1320 to respond to him getting
over and over
I swear....people come online and it's like their is a ******* Superman suit they slide into during Log In
Originally posted by LT1RX7
You all are apparently retarded or live in computer land rather than reality. One second difference at a dragstrip on a 13 sec car is a HUGE margin.
Schools in session:
Try this drive down the road at 100mph when you get to a bridge have someone in the car start a stop watch after one second you are much farther than 8 ft.
Or have someone drive by you at 100mph. They would pass you by more than 8 feet.
The 8 feet is the distance you are INCREASING OVER the other guy at the point you cross the traps. The 154 is the total amount of distance you have accumulated over the entire 1/4 mile.
The first guy was right about the 154 feet, and apparently the only one NOT smoking crack.
The one second difference is relative to a stationary point not a moving point.
Schools out.
Damn for some people that claim to have physics and calculus backgrounds you sure are WRONG BADLY.
You all are apparently retarded or live in computer land rather than reality. One second difference at a dragstrip on a 13 sec car is a HUGE margin.
Schools in session:
Try this drive down the road at 100mph when you get to a bridge have someone in the car start a stop watch after one second you are much farther than 8 ft.
Or have someone drive by you at 100mph. They would pass you by more than 8 feet.
The 8 feet is the distance you are INCREASING OVER the other guy at the point you cross the traps. The 154 is the total amount of distance you have accumulated over the entire 1/4 mile.
The first guy was right about the 154 feet, and apparently the only one NOT smoking crack.
The one second difference is relative to a stationary point not a moving point.
Schools out.
Damn for some people that claim to have physics and calculus backgrounds you sure are WRONG BADLY.
The 8 feet is the distance you are INCREASING OVER the other guy at the point you cross the traps. The 154 is the total amount of distance you have accumulated over the entire 1/4 mile.
Try this drive down the road at 100mph when you get to a bridge have someone in the car start a stop watch after one second you are much farther than 8 ft.
Or have someone drive by you at 100mph. They would pass you by more than 8 feet.
Or have someone drive by you at 100mph. They would pass you by more than 8 feet.
Lol you don't do calculations in relative to moving points very often and if you do your not normally making a finite calculation you are finding the average or calibration curve.
If your going to make fun of people and tell them they are on crack make sure you put the pipe down before you start writing

Btw forgot to add that non of these calculations have anything to do with figuring out the distance between two cars after a 1/4mile race lol
Last edited by ReodDai; Apr 18, 2004 at 07:18 PM.
Joined: Mar 2001
Posts: 30,800
Likes: 646
From: FL-->NJ/NYC again!
Originally posted by AMRAAM4
At what speed in 5th are you dropping to 3rd to take off with boost? I drop to 4th, but am paranoid dropping to third at the speed of 65-70.
At what speed in 5th are you dropping to 3rd to take off with boost? I drop to 4th, but am paranoid dropping to third at the speed of 65-70.
3rd gear redlines at ~100 mph. I have downshifted from 5th to 3rd at ~80 mph hundreds of times since owning my FD with excellent results. Much more than 80 and I would stick with 4th though
Originally posted by respecttheseven
i am just wondering if u guys have any technics i could learn from you. i want to get off the lione faster and get to 5k asap...it just feels groggy right when i start off.... what am i doing wrong...
i am just wondering if u guys have any technics i could learn from you. i want to get off the lione faster and get to 5k asap...it just feels groggy right when i start off.... what am i doing wrong...
Originally posted by respecttheseven
i am just wondering if u guys have any technics i could learn from you. i want to get off the lione faster and get to 5k asap...it just feels groggy right when i start off.... what am i doing wrong...
i am just wondering if u guys have any technics i could learn from you. i want to get off the lione faster and get to 5k asap...it just feels groggy right when i start off.... what am i doing wrong...
Time to make you feel idiotic cause apparently you cant read.
I said that "The 154 is the total amount of distance you have accumulated over the entire 1/4 mile." Meaning over the other guy during the race. and 1000ft is not a quarter mile it is 1320ft accumulated if you are going by what you thought I said.
Again what I said was "Try this drive down the road at 100mph when you get to a bridge have someone in the car start a stop watch after one second you are much farther than 8 ft." Which is the EXACT same thing you are saying. I said it will be much more than 8 feet learn to read before you attempt to insult someone. Notice the MUCH FARTHER THAN 8 FT!!!
Which is exactly why in the previous post I said "The one second difference is relative to a stationary point not a moving point." Again read what I write not what you think I write.
Apparently you need to heed your own advice because you are the one hitting it up.
No they dont but they do illustrate that it will be MUCH more than a car length between 2 cars that run a second difference in the 1/4.
Hey I already said I am in MD right near you so if you want to see Superman we can arrange for a meeting....HERO.
Originally posted by ReodDai
1st part is right.. second part makes you look ignorant. 1000ft is the total amount of distance you have accumulated over the entire 1/4mile =) You are traveling 154fps at 105mph
1st part is right.. second part makes you look ignorant. 1000ft is the total amount of distance you have accumulated over the entire 1/4mile =) You are traveling 154fps at 105mph
Originally posted by ReodDai
Once again you proved you have no clue what you are talking about. After one second going 100mph you would travel 146 feet.. not 8 feet (8 fps is the difference between traveling 100mph and 105mph) The second explain makes no since once again. Except to prove you have no clue what you wear reading lol. If someone passes you going 105mph and your going 100mph then they would pass you by 8fps.
Once again you proved you have no clue what you are talking about. After one second going 100mph you would travel 146 feet.. not 8 feet (8 fps is the difference between traveling 100mph and 105mph) The second explain makes no since once again. Except to prove you have no clue what you wear reading lol. If someone passes you going 105mph and your going 100mph then they would pass you by 8fps.
Originally posted by ReodDai
Lol you don't do calculations in relative to moving points very often and if you do your not normally making a finite calculation you are finding the average or calibration curve.
Lol you don't do calculations in relative to moving points very often and if you do your not normally making a finite calculation you are finding the average or calibration curve.
Originally posted by ReodDai
If your going to make fun of people and tell them they are on crack make sure you put the pipe down before you start writing
If your going to make fun of people and tell them they are on crack make sure you put the pipe down before you start writing
Originally posted by ReodDai
Btw forgot to add that non of these calculations have anything to do with figuring out the distance between two cars after a 1/4mile race lol
Btw forgot to add that non of these calculations have anything to do with figuring out the distance between two cars after a 1/4mile race lol
Originally posted by AMRAAM4
I swear....people come online and it's like their is a ******* Superman suit they slide into during Log In
I swear....people come online and it's like their is a ******* Superman suit they slide into during Log In
I realised the launch is everything. I got 14.5sec on a bogged down launch and 13.4sec on a good launch. This was on crappy 3 years old 225 tires.
I got it to 3k RPM, then dropped the clutch, letting the wheels to spin a bit.
At 13psi boost and about 17psi tire pressure in the back.
I got it to 3k RPM, then dropped the clutch, letting the wheels to spin a bit.
At 13psi boost and about 17psi tire pressure in the back.
Thread
Thread Starter
Forum
Replies
Last Post
thecody59
1st Generation Specific (1979-1985)
40
Aug 23, 2015 06:41 PM







