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Wolf 3D Injector Impedence

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Old Jun 22, 2007 | 02:34 AM
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Injector Impedence

Ok well i'm no tuning guru, bear with me if you don't understand.

I'm running a wolf v4.
I have a 3rd row of RC low impedence injectors 4x550cc (I believe 1.2v each).
The primary and secondary rows are stock (high impedence correct me if i'm wrong something like 11.2 or 12v).

My question is if i wire the the 3rd row to fire with the secondaries or even the primaries will the Wolf driver have enough juice? can i mix high and low impedence injectors?

Another question is ff they don't have enough juice the injectors would just not open correct? or would it burn out the board?

The manual on the wolf says it can handle low impedence injectors as well as the high ones, but never mentions anything about mixing them.

thanks
Peter
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Old Jun 22, 2007 | 11:11 AM
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first of all impedance is measured in ohms, not volts.

second of all, the wolf manual is VERY clear on what injector loads it can support.

section 5.4.1 injector impedance says the wolf can drive an injector load down to 1.2 ohms. Any less resistance than this and the drivers will overheat and the wolf will disable them.

the formula for calculating impedance for parallel wiring is:

1/Rtotal = 1/R1 + 1/R2 + 1/R3 + 1/R4 ...

series is:
Rtotal = R1 + R2 + R3 + R4 ...

If you wire them in series, they will not see full voltage.

I'm pretty sure the RC Eng injectors are either 2.5 or 3ohm for the low resistance injectors (I'm running a pair of them in my primaries).

If you use (2) 2.5 ohm injectors you will have an impedance of 1.25 ohms. This is acceptable as it is just above the wolfs minimum limit.

If you are mixing them with the high impedance injectors youre using on your staged output with your secondaries, it depends on the resistance of the other injectors.

I'm not sure what the resistance of the injectors your using are, but I'll use 12 ohms for an example.

1/Rtotal = 1/2.5 + 1/2.5 + 1/12 + 1/12

Rtotal = 1.0345 Which is below what the wolf driver is said to support.

If your other injectors happenned to be 16 ohms...

Rtotal = 1.081

Now the calculation if you happen to have the 3ohm injectors from rceng and 12ohm secondaries:

1/rtotal = 1/3 + 1/3 + 1/12 + 1/12

rtotal = 1.2


Basically, if the injectors youre wiring in happen to be 3ohms, and the secondaries you have are at LEAST 12ohms, you'll be ok. Otherwise you will be pushing the injector driver beyond its intended limits.
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Old Jun 22, 2007 | 05:00 PM
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Originally Posted by nyt
first of all impedance is measured in ohms, not volts.

second of all, the wolf manual is VERY clear on what injector loads it can support.

section 5.4.1 injector impedance says the wolf can drive an injector load down to 1.2 ohms. Any less resistance than this and the drivers will overheat and the wolf will disable them.

the formula for calculating impedance for parallel wiring is:

1/Rtotal = 1/R1 + 1/R2 + 1/R3 + 1/R4 ...

series is:
Rtotal = R1 + R2 + R3 + R4 ...

If you wire them in series, they will not see full voltage.

I'm pretty sure the RC Eng injectors are either 2.5 or 3ohm for the low resistance injectors (I'm running a pair of them in my primaries).

If you use (2) 2.5 ohm injectors you will have an impedance of 1.25 ohms. This is acceptable as it is just above the wolfs minimum limit.

If you are mixing them with the high impedance injectors youre using on your staged output with your secondaries, it depends on the resistance of the other injectors.

I'm not sure what the resistance of the injectors your using are, but I'll use 12 ohms for an example.

1/Rtotal = 1/2.5 + 1/2.5 + 1/12 + 1/12

Rtotal = 1.0345 Which is below what the wolf driver is said to support.

If your other injectors happenned to be 16 ohms...

Rtotal = 1.081

Now the calculation if you happen to have the 3ohm injectors from rceng and 12ohm secondaries:

1/rtotal = 1/3 + 1/3 + 1/12 + 1/12

rtotal = 1.2


Basically, if the injectors youre wiring in happen to be 3ohms, and the secondaries you have are at LEAST 12ohms, you'll be ok. Otherwise you will be pushing the injector driver beyond its intended limits.
ok so basically anything higher then 1.2 ohms i'm fine. but anything lower it won't work?
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Old Jun 22, 2007 | 09:32 PM
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hmmm i was thinking is it possible to uhh mix series and parrallel wiring? making 2 550 injectors in series and then paralleling it to the line?
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Old Jun 23, 2007 | 12:08 AM
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the thing about wiring things like this in series, it doesn't work =]

2 injectors in series = 6v, 4 injectors = 3v.

I don't think that will work so hot =]
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Old Jun 23, 2007 | 12:22 AM
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Originally Posted by nyt
the thing about wiring things like this in series, it doesn't work =]

2 injectors in series = 6v, 4 injectors = 3v.

I don't think that will work so hot =]
is it because of the mixed impedances?

was my first assumption right? anything higher then 1.2ohms i'm golden?

and does anyone have the impedances for the stock injectors, can't seem to find them.

thanks
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Old Jun 23, 2007 | 04:03 PM
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In a parallel arrange, the resulting impedance is ALWAYS lower than the lowest individual value.
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