Got the BIG brake kit for my baby!!
#51
Super Snuggles
Originally Posted by turbojeff
What you are thinking is 1000lbs spread over twice the area I think = 1/2 the force.
#52
Super Snuggles
Originally Posted by maxcooper
Your understanding is flawed -- force increases with piston area for a given line pressure. 1000 psi spread over twice the surface area is 1000 psi over the whole area, but there is more area, so the resulting force is greater. The units of pressure are "pounds per square inch", so if you have more square inches (bigger pistons), you are going to have more pounds of force pinching the rotor:
1000 psi times 2 square inches of piston area = 2000 lbs of force
1000 psi times 4 square inches of piston area = 4000 lbs of force
1000 psi times 2 square inches of piston area = 2000 lbs of force
1000 psi times 4 square inches of piston area = 4000 lbs of force
1,001 psi would be more force.
#53
2/4 wheel cornering fiend
The main reason for calipers with more than four opposed pistons is that the brake pads last longer. Six-piston calipers and the like were developed from endurance racing, where component life during the race is obviously of critical importance. While in theory it would provide more braking power, it's not that simple. It's not just the clamping force that provides the braking power; it's the friction created between the disc and pads. Simply clamping down with more force doesn't necessarily provide more friction. There's a hell of a lot that goes into pad formulas in relation to the caliper and disc design.
If simply adding more pistons to the caliper created more braking force, you'd see 12-piston calipers or whatnot.
If simply adding more pistons to the caliper created more braking force, you'd see 12-piston calipers or whatnot.
#54
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Originally Posted by Fritz Flynn
You can talk formulas etc....all day long but once installed you'll find the rear never settlles or locks and the front dives harder and chirps/locks everytime under threshold braking.
So IMO a front BBK will increase front brake bias on an otherwise stock car.
So IMO a front BBK will increase front brake bias on an otherwise stock car.
#55
Originally Posted by jimlab
If I have a vice with a 4" jaw and I put 1,000 psi of pressure on something placed between the jaws, am I putting any more force on the object if I applied the same 1,000 psi with an 8" jaw? No... 1,000 psi is 1,000 psi regardless of the amount of surface area involved.
1,001 psi would be more force.
1,001 psi would be more force.
Pretend you have a hydraulic vise and a foot pump to operate it. Assume that if you push on the foot pump with 100 lbs of force, you get 1000 psi of line pressure (it has a piston with 1/10 square inches of area, or a 1 square inch piston with a 10:1 lever, etc.). You have two vises, one has a piston with 2 square inches of area, and the other has a piston with 4 square inches of area. If you push on the foot pump with 100 lbs of force, giving 1000 psi line pressure, the vise with 2 square inches of piston area will clamp with 2000 lbs of force. The vise with 4 square inches of piston area will clamp with 4000 lbs of force under the same conditions, but the foot pump will move further before you get to the final state of sitting there with 100 lbs on the pedal. Now install the foot pump in your car and put the vises in position to clamp your rotors and you have an automotive braking system.
Here's a howstuffworks link with some more hydraulic info:
http://science.howstuffworks.com/hydraulic1.htm
-Max
#56
I found a cool page on howstuff works that explains how equal pressures are maintained in the front and rear brake circuits by the master clyinder without the need for a pressure differential valve to join the circuits (as I previously suspected):
http://auto.howstuffworks.com/master-brake1.htm
-Max
http://auto.howstuffworks.com/master-brake1.htm
-Max
#57
Originally Posted by Kento
The main reason for calipers with more than four opposed pistons is that the brake pads last longer. Six-piston calipers and the like were developed from endurance racing, where component life during the race is obviously of critical importance. While in theory it would provide more braking power, it's not that simple. It's not just the clamping force that provides the braking power; it's the friction created between the disc and pads. Simply clamping down with more force doesn't necessarily provide more friction. There's a hell of a lot that goes into pad formulas in relation to the caliper and disc design.
Originally Posted by Kento
If simply adding more pistons to the caliper created more braking force, you'd see 12-piston calipers or whatnot.
-Max
#58
Do it right, do it once
iTrader: (30)
Originally Posted by jimlab
You're right, 1,000 psi is 1,000 psi, whether it's measured for a single square inch or a city block.
Doesn't matter if it is a 4" jaw or 8" jaw.
#60
Originally Posted by mad_7tist
it will now take twice as much force to twist out the object. (assuming no friction differences material deflection etc)
-Max
#63
Originally Posted by mad_7tist
do i want to know how or why you have that link???
-Max
#64
2/4 wheel cornering fiend
Originally Posted by maxcooper
I agree that it isn't JUST clamping force that determines brake effectiveness, but it should be clear that for a given system, more clamping force does indeed increase the amount of braking you get. That's precisely what happens when you push harder on the pedal.
The statement that using six-pot (or more) calipers will automatically gain you an increase in braking power over a well-designed four-piston caliper is a myth.
#66
Super Snuggles
Uo
Originally Posted by maxcooper
Here's a howstuffworks link with some more hydraulic info:
http://science.howstuffworks.com/hydraulic1.htm
http://science.howstuffworks.com/hydraulic1.htm
Using the example on that page, the 2" piston (3.14 sq. in.) moves the 6" (28.26 sq. in.) 1 inch when it travels 9, because the larger piston is 9 times the size of the smaller one.
If you increase the size of the slave piston to 7" (38.48 sq. in.), for example, the slave is now 12.25 times the size of the master. Pushing the master piston 9" now only moves the slave piston 0.73". So a 100 lb. downforce on the master piston results in... the same 900 lb. upforce on the slave piston, even though it's larger in diameter.
100 lb. * 12.25 = 1,225 lbs. * 0.73 = 894.25 lbs.
In order to increase the force on the slave piston, the master piston has to travel farther (and your brake pedal only travels so far), or the master piston must be increased in size (larger master cylinder). In the end, it's an increase in line pressure that increases clamping pressure... not just increasing the piston area.
Last edited by jimlab; 04-03-05 at 07:44 PM.
#67
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Originally Posted by HDP
Aren't we really applying the pressure to the fluid and not to the caliper itself? Wouldn't the fluid compress at the same rate reguardless if more was required to fill the larger caliper?
#68
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Jim, I think you're not seeing the forest through the trees here...the facts are that bias is changed by any of the following factors:
*rotor diameter
*brake pad friction coefficient
*caliper piston diameter
Any scientific reasoning you are attempting that disproves any of the above is flawed. I really wish David Zeckhausen from Zeckhausen racing would pop in and clear all this up.....
*rotor diameter
*brake pad friction coefficient
*caliper piston diameter
Any scientific reasoning you are attempting that disproves any of the above is flawed. I really wish David Zeckhausen from Zeckhausen racing would pop in and clear all this up.....
#69
A Fistfull of Dollars!
iTrader: (2)
Originally Posted by rynberg
Nope, fluid is essentially uncompressible. Take a glass filled with water. Take a disk the same size as the glass. Try to compress the water. Ok, don't REALLY try it, because I don't want you to cut yourself...
#70
Originally Posted by jimlab
Look at the hydraulic multiplication example. If you increase the size of the "slave" (larger) piston, it won't move as far with the same travel of the "master" (smaller) piston. It will take a longer stroke of the master piston or a larger diameter master piston to move a larger slave piston the same distance as the original,
and exert the extra force you're talking about. Either of those options results in an increase in line pressure.
Using the example on that page, the 2" piston (3.14 sq. in.) moves the 6" (28.26 sq. in.) 1 inch when it travels 9, because the larger piston is 9 times the size of the smaller one.
If you increase the size of the slave piston to 7" (38.48 sq. in.), for example, the slave is now 12.25 times the size of the master. Pushing the master piston 9" now only moves the slave piston 0.73". So a 100 lb. downforce on the master piston results in... the same 900 lb. upforce on the slave piston, even though it's larger in diameter.
100 lb. * 12.25 = 1,225 lbs. * 0.73 = 894.25 lbs.
If you increase the size of the slave piston to 7" (38.48 sq. in.), for example, the slave is now 12.25 times the size of the master. Pushing the master piston 9" now only moves the slave piston 0.73". So a 100 lb. downforce on the master piston results in... the same 900 lb. upforce on the slave piston, even though it's larger in diameter.
100 lb. * 12.25 = 1,225 lbs. * 0.73 = 894.25 lbs.
100 lbs of force on a 3.14 in^2 master piston = 100 / 3.14 = 31.85 psi
31.85 psi * 28.26 in^2 (6") slave piston = 900 pounds of force
31.85 psi * 38.48 in^2 (7") slave piston = 1226 pounds of force
There is no magic -- you are just trading stroke for force, much like a lever or cheater bar on a wrench. But in the case of brakes, once the pads hit the rotor, it's all about force -- you aren't actually moving the pistons anymore.
In order to increase the force on the slave piston, the master piston has to travel farther (and your brake pedal only travels so far), or the master piston must be increased in size (larger master cylinder). In the end, it's an increase in line pressure that increases clamping pressure... not just increasing the piston area.
(1) Pedal force translates directly to line pressure for a given pedal and MC arrangement.
(2) The rear brakes have not changed, so you'll get the same torque for a given line pressure.
-Max
#72
Super Snuggles
Originally Posted by maxcooper
If you push the brake pedal just as hard(1) before and after the upgrade, you will get more braking torque with the upgraded brakes than you did with the stockers
For example, Roger Mandeville's big brake setup re-used the stock calipers with a larger diameter rotor. What was the benefit? More mass in the rotor to shed heat more rapidly. Did it increase braking torque? Sure, but so what. You can reach lock-up a little sooner than you could before. Big deal. It doesn't decrease stopping distance any.
The stock calipers are not the limitation. As I've said several times now, they provide more than ample clamping force to lock up the rotors. The limitation is the size of the stock rotors. What did Mazda do with the '99-up FDs? Increased the diameter of the rotors.
Do the '99-spec rear calipers balance out a big brake kit? Sure, but if they have the same piston area as the '93-'95 rear calipers, how are they doing that? With a proportional increase in brake torque provided by moving them farther away from the wheel center. Fronts and rears now lock up at the same time, problem solved. No change in pad size. No change in piston diameter.
#75
Originally Posted by jimlab
Let's stop right there... of course you'll get more braking torque; you moved the caliper farther away from the center of the wheel. You'd get more brake torque from the stock calipers if you did the same thing.
But calipers with more piston area mounted in the same position as the stock calipers would also increase the braking torque, since they will pinch harder when you push the pedal with the same force (which will give a fixed amount of rear braking torque no matter which fronts you have installed).
Originally Posted by jimlab
For example, Roger Mandeville's big brake setup re-used the stock calipers with a larger diameter rotor. What was the benefit? More mass in the rotor to shed heat more rapidly. Did it increase braking torque? Sure, but so what. You can reach lock-up a little sooner than you could before. Big deal. It doesn't decrease stopping distance any.
Originally Posted by jimlab
The stock calipers are not the limitation. As I've said several times now, they provide more than ample clamping force to lock up the rotors. The limitation is the size of the stock rotors. What did Mazda do with the '99-up FDs? Increased the diameter of the rotors.
Originally Posted by jimlab
Do the '99-spec rear calipers balance out a big brake kit? Sure, but if they have the same piston area as the '93-'95 rear calipers, how are they doing that? With a proportional increase in brake torque provided by moving them farther away from the wheel center. Fronts and rears now lock up at the same time, problem solved. No change in pad size. No change in piston diameter.
-Max
Last edited by maxcooper; 04-03-05 at 11:13 PM.