Why bigger turbos make more HP at the same PSI....
#26
Originally Posted by dubulup
thanks man! I just sold the entire set-up.
Powder coated Wrinkle black is the cleanest thing under a hood...IC is paint. I always wondered, which was better for keeping heat out (or letting heat out??) powder or anodize
To: Big_Rizzlah
the way I think of it is...big turbo pushes air easily and efficiently thru intake, and exit easily thru exhaust = less backpressure on engine...rinse and repeat complete circle.
Powder coated Wrinkle black is the cleanest thing under a hood...IC is paint. I always wondered, which was better for keeping heat out (or letting heat out??) powder or anodize
To: Big_Rizzlah
the way I think of it is...big turbo pushes air easily and efficiently thru intake, and exit easily thru exhaust = less backpressure on engine...rinse and repeat complete circle.
#28
2/4 wheel cornering fiend
Originally Posted by wanklin
less safe
#29
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Okay I still can't get this. (sorry)
All other things staying the same i don't see how a larger compressor housing *can* make more power than a small one. I understand that if you increase the efficiency of the whole system (larger diameter intake, intercooler, etc... downpipe, cat/midpipe, etc.. how more flow could be achieved
but if the flow rate stays the same and the pressure stays the same then how does a larger compressor move more air? Imagine pushing positive pressure into a jar at sea level: you use a small compressor so it takes a while to fill the jar but ultimately you manage to cram the jar with 24.4psi (14.4 atmospheric +10psi) of air. Since the compressor is already spun up the next jar won't take nearly as long to fill.
When you use a larger compressor it doesn't have to spin up as much to move the volume of air that brings the atmospheric pressure inside the jar to 24.4psi.
Both jars ultimately will contain both the same pressure and the same total volume of air (at atmospheric pressure) unless one compressor overheated the air- bringing me too.....
But compressor efficiency doesn't make a big difference unless one of your compressors is out of it's efficiency range.
I hope you all followed that.
All other things staying the same i don't see how a larger compressor housing *can* make more power than a small one. I understand that if you increase the efficiency of the whole system (larger diameter intake, intercooler, etc... downpipe, cat/midpipe, etc.. how more flow could be achieved
but if the flow rate stays the same and the pressure stays the same then how does a larger compressor move more air? Imagine pushing positive pressure into a jar at sea level: you use a small compressor so it takes a while to fill the jar but ultimately you manage to cram the jar with 24.4psi (14.4 atmospheric +10psi) of air. Since the compressor is already spun up the next jar won't take nearly as long to fill.
When you use a larger compressor it doesn't have to spin up as much to move the volume of air that brings the atmospheric pressure inside the jar to 24.4psi.
Both jars ultimately will contain both the same pressure and the same total volume of air (at atmospheric pressure) unless one compressor overheated the air- bringing me too.....
But compressor efficiency doesn't make a big difference unless one of your compressors is out of it's efficiency range.
I hope you all followed that.
#30
Mr. Links
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Originally Posted by NissanConvert
but if the flow rate stays the same and the pressure stays the same then how does a larger compressor move more air?
http://forums.nasioc.com/forums/arch.../t-359824.html
They demonstrate the air movement differences between a few different setups.
Have you ever looked at computer CPU/Case fans? Start comparing the fan size, with the rpms and the CFM it moves; similar concept.
#31
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Yes, but with Case fans you're really only worried about the size and the rpm. There aren't any serious restrictions in the case or in the atmosphere.
So if i were to take a gt42r and strap it on a bone stock car reduce the compressor outlet to stock and run 10psi how would i make more power than the stock twins at the same manifold pressure?
So if i were to take a gt42r and strap it on a bone stock car reduce the compressor outlet to stock and run 10psi how would i make more power than the stock twins at the same manifold pressure?
#32
On flats
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yes, dubulup, i agree 100%. That's what I was trying to say, you just said it much more eloquently.
for some reason, I literally chuckled out loud when I read big dog rizza, I love that my screenname/avatar serves its intended purpose, I think I wanna to change it though.
ryan
for some reason, I literally chuckled out loud when I read big dog rizza, I love that my screenname/avatar serves its intended purpose, I think I wanna to change it though.
ryan
#34
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Originally Posted by NissanConvert
Yes, but with Case fans you're really only worried about the size and the rpm. There aren't any serious restrictions in the case or in the atmosphere.
So if i were to take a gt42r and strap it on a bone stock car reduce the compressor outlet to stock and run 10psi how would i make more power than the stock twins at the same manifold pressure?
So if i were to take a gt42r and strap it on a bone stock car reduce the compressor outlet to stock and run 10psi how would i make more power than the stock twins at the same manifold pressure?
#35
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Originally Posted by Fritz Flynn
The charge temp from that gt42 will be much colder
#36
2/4 wheel cornering fiend
Originally Posted by wanklin
denser air+less backpressure = more power = kaboom
#37
Originally Posted by Kento
Just because you're making more power doesn't mean you'll blow the engine. I'd say the chances are greater with a small turbo working hard near the edge of its efficiency range heating up the intake charge and forming a more enticing environment for detonation to occur.
Last edited by wanklin; 04-24-07 at 06:01 PM.
#38
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Originally Posted by NissanConvert
When you say "much" what do you mean? On my twins at ~80mph i see IATs about 20c over ambient.
#40
2/4 wheel cornering fiend
Originally Posted by wanklin
Yes but a hotter charge will contain less air = less fuel injected = less kaboom.
EDIT: Not trying to be an *** here. Just clarifying what can be a very misleading statement.
Last edited by Kento; 04-24-07 at 06:15 PM.
#41
2/4 wheel cornering fiend
Originally Posted by NissanConvert
When you say "much" what do you mean? On my twins at ~80mph i see IATs about 20c over ambient.
#42
Ignore that BS above as I understand how detonation works, I was just giving a BS reponse to an ambiguous question, and made myself look like I don't know what the hell I'm talking about. lol. I really agree with you on all counts this thread just brought me back to a previous one started by some guy who wanted to run a GT35R on a stock ECU. Run a larger turbo on a stock ECU and you lean out. That was my thought process.
detonation cares about ratio and temperature (not volume) as you kindly pointed out.
detonation cares about ratio and temperature (not volume) as you kindly pointed out.
Last edited by wanklin; 04-24-07 at 06:28 PM.
#43
2/4 wheel cornering fiend
Originally Posted by wanklin
Ignore that BS above as I understand how detonation works, I was just giving a BS reponse to an ambiguous question, and made myself look like I don't know what the hell I'm talking about. lol. I really agree with you on all counts this thread just brought me back to a previous one started by some guy who wanted to run a GT35R on a stock ECU. Run a larger turbo on a stock ECU and you lean out. That was my thought process.
detonation cares about ratio, not volume and temperature as you kindly pointed out.
detonation cares about ratio, not volume and temperature as you kindly pointed out.
#45
Don't worry be happy...
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Originally Posted by big_rizzlah
well let's simplify this. . .ALOT.
PV=nRT -> PV/nRT = 1 -> P1V1/n1R1T1 = P2V2/n2R2T2
For a given setup. . .ALL things except turbos identical, for the same boost
P1 = P2
V1 = V2
R1 = R2 = constant
therefore
n1T1 = n2T2 where n is the mass of air.
Let's call the smaller turbo 1 and the larger turbo 2
n2 = n1T1/T2
in other words. . .the mass of air that the larger turbo pushes at the same pressure, all things being equal, is equal to the mass of air the smaller turbo pushed times the ratio of temperatures. Basically, the adiabatic efficiency with which the larger turbo can compress n2 amount of air is greater such that the temperature of the compressed air is less so that the above relationship is satisfied.
Let's look at it another way, holding the same amount of air each is pushing constant (same power output assuming equivalent tuning since the mass of air is what dictates power made assuming equivalent combustion (tuning)).
P1V1/n1R1T1 = P2V2/n2R2T2
simplifies to
P1/T1 = P2/T2
P2 = P1T2/T1
again, since the larger turbo can compress the same mass of air more easily, less work is done, less heat is generated, T2 is less, therefore the ratio T2/T1 is less than one, therefor P2 < P1, therefore, the larger turbo makes more power (pushes a larger MASS of air) at a lower pressure than the smaller turbo.
This is a really simplistic way to look at it, but most of the assumptions of the ideal gas law are valid *enough* for this to work. there are much more complex dynamics at work that both compliment and counteract, but for basic understanding's sake. . .it'll work.
Now everyone bust out your physics 1 book and study up.
Or I'm just wrong and a hugely pompous ***. . .either way
ryan
PV=nRT -> PV/nRT = 1 -> P1V1/n1R1T1 = P2V2/n2R2T2
For a given setup. . .ALL things except turbos identical, for the same boost
P1 = P2
V1 = V2
R1 = R2 = constant
therefore
n1T1 = n2T2 where n is the mass of air.
Let's call the smaller turbo 1 and the larger turbo 2
n2 = n1T1/T2
in other words. . .the mass of air that the larger turbo pushes at the same pressure, all things being equal, is equal to the mass of air the smaller turbo pushed times the ratio of temperatures. Basically, the adiabatic efficiency with which the larger turbo can compress n2 amount of air is greater such that the temperature of the compressed air is less so that the above relationship is satisfied.
Let's look at it another way, holding the same amount of air each is pushing constant (same power output assuming equivalent tuning since the mass of air is what dictates power made assuming equivalent combustion (tuning)).
P1V1/n1R1T1 = P2V2/n2R2T2
simplifies to
P1/T1 = P2/T2
P2 = P1T2/T1
again, since the larger turbo can compress the same mass of air more easily, less work is done, less heat is generated, T2 is less, therefore the ratio T2/T1 is less than one, therefor P2 < P1, therefore, the larger turbo makes more power (pushes a larger MASS of air) at a lower pressure than the smaller turbo.
This is a really simplistic way to look at it, but most of the assumptions of the ideal gas law are valid *enough* for this to work. there are much more complex dynamics at work that both compliment and counteract, but for basic understanding's sake. . .it'll work.
Now everyone bust out your physics 1 book and study up.
Or I'm just wrong and a hugely pompous ***. . .either way
ryan
PV=NRT: It is a relationship between pressure , Volume, molecules, and temperature. And really applies more to intercooling rather than turbos.
for this application:
P= NRT1/V = 10 lbs
P= NRT2/V = 10 lbs
temperature goes down the N (number of molecules) has to go up in order to maintain the same pressure. More oxygen molecules in combustion chamber = more power.
Just so you all know comparing 10 psi single Vs 10 psi twins is apples to oranges.
Single turbo:
Pressure at the manifold = 10 psi
Twins:
Pressure at the manifold = 10 psi
CFM of single > than CFM of twins
Using a single, the end result is alot more oxygen molecules at the COMBUSTION chamber due to a higher CFM. In the combustion chamber: Pressure using a single does not = the same pressure as using the twins.
its are all about CFM. PV=NRT directly applied at the manifold, where the pressure is measured, does NOT depent on how much air is moving through it.
#46
The engine isn't really seeing 10PSI, it's seeing whatever the turbo can get into the intake ports before they close. That's why flow matters. A large turbo will move more air in that short window of time. If the engine was getting 10PSI boost internally with both setups flow wouldn't mean squat. Flow means nothing once the ports are sealed.
#47
Originally Posted by wanklin
You mean the volume of the copressor housing? Are you talking about spool up time Ramy?
If the turbo has not spooled you will not get sufficient boost so the issue is null and void.
If the turbo has not spooled you will not get sufficient boost so the issue is null and void.
For example, the stock twins are considered spooling until 10psi, right? And at 10 psi they make 255hp, correct? If you stuck a GT40 on a 3rd gen for example (which is capable of much higher boost than the stocker), and saw the power output at 10psi, you'd see it'll make MORE than the stockers' 255hp, despite it still being IN SPOOL. Why? Because your reference point (when you're out of spool) has changed.
In simple terms, just b/c a turbo is in spool does NOT mean it isn't creating enough power. A spooling turbo produces boost, and ANY level of boost creates power. No nothing's null and void here
I think this whole discussion is based on the assumption that the turbo has spooled up already in both scenarios.
Accepting this,
A small turbo rotating at a higher RPM can achieve the same flow as a larger turbo rotating at a lower RPM if the exhaust back pressure and intake tempts are held constant.
RPM does play a role.
If they were rotating at the same speed the larger turbo would compress more air and higher manifold pressure would result.
That's what we all agree upon. What we're basically saying is that higher charge velocity is the result of lower backpressure and the power is further increased through greater charge density at lower temps.
~Ramy
#48
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I think we've established that more CFM = more power and that a larger compressor will deliver more CFM at a given MAP. However, if the rest of the system does not allow for the increase in flow how does it?
#49
2/4 wheel cornering fiend
Originally Posted by NissanConvert
I think we've established that more CFM = more power and that a larger compressor will deliver more CFM at a given MAP. However, if the rest of the system does not allow for the increase in flow how does it?
If you're referring to the stock twin setup, all you have to do is look at the people with BNR Stage 3 setups (or those lucky enough to have the old M2 BB twins, or the even rarer Australian SP versions) to see that even with the restrictive stock exhaust manifold design, you'll still see an increase in power relative to boost, and that's even with turbos that are only slightly larger than stock. Does this mean you can just fab a Cummins diesel-sized huffer onto each end and you'll end up with more power? No, of course not. But all else being equal...
#50
Senior Member
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You guys are making it way more complicated than it needs to be. The ideal gas law doesn't apply, and equations aren't going to simplify it at all.
A large turbo at a given boost pressure supplies more mass of air per time than a small turbo at a given boost pressure. That's why they are different, pressure does not tell you how much air you are getting, and neither does volumetric flow (CFM) by itself although they can give you an idea.
Kevin
A large turbo at a given boost pressure supplies more mass of air per time than a small turbo at a given boost pressure. That's why they are different, pressure does not tell you how much air you are getting, and neither does volumetric flow (CFM) by itself although they can give you an idea.
Kevin